Home
Class 12
MATHS
The locus of the centroid of the triangl...

The locus of the centroid of the triangle with vertices at `(acostheta,asintheta)`, `(bsintheta-bcostheta)` and `(1,0)` is (here, `theta` is a parameter)

A

`(3x+1)^(2)+9y^(2)=a^(2)+b^(2)`

B

`(3x-1)^(2)+9y^(2)=a^(2)-b^(2)`

C

`(3x-1)^(2)+9y^(2)=a^(2)+b^(2)`

D

`(3x+1)^(2)+9y^(2)=a^(2)-b^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • LIMITS AND CONTINUITY

    SIA PUBLICATION|Exercise Problems|46 Videos

  • MATRICES

    SIA PUBLICATION|Exercise PROBLEMS|52 Videos

Similar Questions

Explore conceptually related problems

Locus of centroid of the triangle whose vertices are (acostheta,asintheta),(bsintheta,-bcostheta) and (2,0) where theta is a parameter is

Locus of centroid of the triangle whose vertices are (a cos t, a sin t ) , (b sin t - b cos t ) and (1, 0) where t is a parameter, is

The area of the triangle with vertices (a, 0), (a cos theta, b sin theta), (a cos theta, -b sin theta) is

Equation of the locus of the centroid of the triangle whose vertices are (a cos k, a sin k),(b sin k, -b cos k) and (1,0) , where k is a perameter, is

Equation of the locus of the centroid of the triangle whose vertices are (acos k, a sin k),(b sin k, -b cos k) and (1,0) where k is a p arameter is

The maximum value of the area of the triangle with vertices (a,0) ,(a cos theta, b sin theta ) , (a cos theta, -b sin theta) is

The locus of the point (a(costheta+sintheta),b(costheta-sintheta)) , where theta is the parameter, is

Show that the locus of the point of inter section of the lines x cos theta +y sin theta =a, x sin theta -y cos theta = b, theta is a parameter is a circle.

Locus of the point (cos theta +sin theta, cos theta - sin theta) where theta is parameter is

Find the locus of point (tantheta+sintheta,tantheta-sintheta) where theta is a parameter.