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If the length of the tangent from (h,k) to the circle `x^(2)+y^2=16` is twice the length of the tangent from the same point to the circle `x^(2)+y^(2)+2x+2y=0`, then

A

`h^(2) + k^(2) + 4h + 4k + 16 = 0`

B

`h^(2) + k^(2) + 3h + 3k = 0`

C

`3h^(2) + 3k^(2) + 8h + 8k + 16 = 0`

D

`3h^(2) + 3k^(2) + 4h + 4k + 16 = 0`

Text Solution

Verified by Experts

The correct Answer is:
C
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