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The centre of the circle r^(2) - 4r (cos...

The centre of the circle `r^(2) - 4r (cos theta + sin theta) - 4 = 0` in cartesian coordinates is

A

(1, 1)

B

(-1, -1)

C

(2, 2)

D

(-2, -2)

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The correct Answer is:
C
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