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If y = (lot (e) x)/(x) and z = log (e) x...

If `y = (lot _(e) x)/(x) and z = log _(e) x,` then ` (d ^(2) y)/(dz^(2)) + (dy)/(dz) =`

A

`e^(-z)`

B

`2e^(-z)`

C

`ze^(-z)`

D

`-e^(-z)`

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The correct Answer is:
D
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