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If f is defined in [1, 3] by f(x)=x^3+bx...

If f is defined in [1, 3] by `f(x)=x^3+bx^2+ax` such that `f(1) - f(3) = 0` and f'(c) =0 where `c=2+1/root()3`, then (a, b) =

A

`(-6,11)`

B

`(2-1/root()3,2+1/root()3)`

C

`(11,-6)`

D

`(6,11)`

Text Solution

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The correct Answer is:
C
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