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SIA PUBLICATION-DEFINITE INTEGRALS-PROBLEMS
- The area of the region bounded by the curves y=9x^2 and y=5x^2 + 4 (in...
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- int(0)^(p//2) (16x sin x cosx dx)/(sin^4 x+cos^4 x)
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- int(0)^(1) sqrt((1-x)/(1+x)dx=
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- int(0)^(pi/4) (sinx + cosx)/(3+sin2x) dx=
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- int(-1)^(1) (sqrt(1+x+x^2)-sqrt(1-x+x^2))/(sqrt(1+x+x^2)+sqrt(1-x+x^2)...
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- The area of the region described by {(x,y)//x^2 + y^2 le 1 and y^2 le ...
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- By the definition of the definite integral, the value of underset(n-oo...
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- int(0)^(pi//6) cos^4 3 theta.sin^2 6 theta d theta equals to
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- The area (in sq. units) of the region bounded by x=-1,x=2,y=x^2+1 and ...
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- int(0)^(b) (dx)/(1+x^2)= int(b)^(oo) (dx)/(1+x^2), then b is equal to
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- The area (in sq. units) bounded by the curves x=-2y^2 and x=1-3y^2 is
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- If a gt0, then int(-pi)^(pi) (sin^2 x)/(1+a^x)dx is equal to
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- The area (in sq. units) bounded by the curves y^2 = 4x and x^2= 4y is
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- The area (in square units) of the region bounded by the curves x=y^2 a...
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- If I(a) = int(0)^(pi//4) tan^(n) theta d theta for n=1,2,3,…, then I(n...
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- If I(n) = int(0)^(pi//2) tan^(n) xdx, then I2 + I4, I3+I5,I4 + I6,…., ...
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- The area (in square units) of the region enclosed by the two circles x...
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- int(0)^(pi) (1)/(1+sinx)dx is equal to
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- The line x=(pi)/(4) divides the area of the region bounded by y=sinx, ...
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- int(0)^(1) x^(3//2) sqrt(1-x) dx is equal to
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