" (c) "(1)/(x+x log x)[NCl

The value of int(1)/(x+x log x)dx is 1+log x(b)x+log x(c)x log(1+log x)(d)log(1+log x)

int (1)/( x (log x) log (log x) ) dx is equal to a) log (log x) + C b) log | log (x log x) + C c) log | log | log (log x) || + C d) log | log (log x) | + C

int (1)/(x ^(3)) [log x ^(x) ] ^(2) dx = p (log x ) ^(3) + c Then p = .............

int (log x)/(x^(2))dx is equal to a) (log x)/(x) + (1)/(x^(2)) +C b) -(log x)/(x) + (2)/(x) + C c) -(log x)/(x) - (1)/(2x) + C d) -(log x)/(x) - (1)/(x) + C

int(log(x+1)-log x)/(x(x+1))dx= (A) log(x-1)log x+(1)/(2)(log x-1)^(2)-(1)/(2)(log x)^(2)+c (B) (1)/(2)(log(x+1))^(2)+(1)/(2)(log x)^(2)-log(x+1)log x+c (C) -(1)/(2)(log(x+1)^(2))-(1)/(2)(log x)^(2)+log x*log(x+1)+c (D) [log(1+(1)/(x))]^(2)+c

If x^(y)=e^(x-y), then (dy)/(dx) is (1+x)/(1+log x)(b)(1-log x)/(1+log x)(c) not defined (d) (log x)/((1+log x)^(2))

intx^(3) log x dx is equal to A) (x^(4) log x )/( 4) + C B) (x^(4))/( 8) ( log x - ( 4)/( x^(2)))+C C) (x^(4))/( 16) ( 4 log x -1) +C D) (x^(4))/( 16) ( 4 log x +1) + C

int e^(x log a ) e^(x) dx is equal to A) (a^(x))/( log ae) + C B) ( e^(x))/( 1+log a ) + C C) ( ae )^(x) +C D) ((ae)^(x))/( log ae) +C