If `y={(log)_(cosx)sinx}{(log)_(sinx)cosx}^(-1)+sin^(-1)((2x)/(1+x^2)),`fin d`(dy)/(dx)a tx=pi/4`

If y={(log)cos x sin x}{(log)_(sin x)cos x}^(-1)+sin^(-1)((2x)/(1+x^(2))) fin d (dy)/(dx)atx=(pi)/(4)

If y=((log)_(cosx)sinx)((log)_(sinx)cosx)+sin^(-1)(2x)/(1+x^2) , then (dy)/(dx) at x=pi/2 is equal to.......

If y=(log_(cosx)sinx)(log_(sinx)cosx)+"sin"""^(-1)(2x)/(1+x^(2)) , then (dy)/(dx) at x=(pi)/(2) is equal to

Find the derivative with respect to x of ((log)_(cosx)sinx)((log)_(sinx)cosx)^(-1)+sin^(-1)((2x)/(1+x^2)) at x=pi/4 .

Slove (2sinx-cosx)(1+cosx)=sin^2x

If y=(e^(2x)cosx)/(x sinx),then(dy)/(dx) =

If y=tan^(-1)((sinx+cosx)/(cosx-sinx))," then "(dy)/(dx)" at "x=(pi)/(4)

If y=(cosx-sinx)/(cosx+sinx)," then "(d^(2)y)/(dx^(2)):(dy)/(dx)=

int(sinx-cosx)/(sqrt(sin2x-(1)/(2)))dx=