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If the kinetic energy of sa particle is ...

If the kinetic energy of sa particle is reduced to half .Eebroglie wave length becomes.

A

2 times

B

`1/sqrt(2) times`

C

4 times

D

`1/sqrt(2)` times

Text Solution

Verified by Experts

The correct Answer is:
d
Debroglie wavwlength `(lambda)=h/sqrt(2mKE)`
`implies (lambda_1)/(lambda_2)=sqrt((KE)/(KE_1))`
`lambda_2=sqrt((KE_1)/(KE_2))xxlambda_1=sqrt((KE_1)/((KE_2)/2))xxlambda_1(thereforeKE_2=(KE_1)/(2))`
`implies lambda_2=sqrt(2)lambda_1`
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