The energy of an electron present in Bohr's second orbit of hydrogen atom is

Options

A. `-1312 J` `atom ^(-1)`
B. `-328KJ mol^(-1)`
C. `-328J, mol^(-1)`
D. `-164KJ, mol^(-1)`

Answer

b

Explanation

Energy of an electron in `n^(th)` orbit,
`E_n=-1311.8[(z^(2))/(n^(2))]KJ mol ^(-1)`
For hydrogen atom, Z=1
For Bohr.s orbit,`n_2=2`
`therefore` Energy of electron in `n_2` orbit `=-1311.8[(1^(2))/(2^(2))]`
`=-327.95 KJ mol^(-1)`
`=-328 KLJ mol ^(-1)`