in the Bohr hydrogen atom, the electronic transition emmiting light of longest wavelength is

Options

A. `n=2` to`n=3`
B. `n=4` to `n=3`
C. `n=3` to `n=2`
D. `n=2`to`n=1`

Answer

b

Explanation

Emitting light of longest wavelength will have low energy and if the principle quantum number increases,the difference between the energy of two orbits decreases. Therefore,n=4 to n=3 refers the lower energy.