The De-Broglie wavelenth of a particle with mass 1 g and velocity `100 ms^(-1)` is

Options

A. `6.63xx10^(-35)m`
B. `6.63xx10^(-34)m`
C. `6.625xx10^(-33)m`
D. `6.63xx10^(-32)m`

Answer

c

Explanation

Mass,`m=1g=10^(-3) kg`
Velocity,`v=100ms^(-1)`
`therefore`De-=Vroglie wavelength of particls is given by
`lambda=h/(mv)=(6.625xx10^(-34))/(10^(-3)xx100)(therefore h=6.625xx10^(-34))`
`=6.625xx10^(-33)m`