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Ammonia on reaction with chlorine forms ...

Ammonia on reaction with chlorine forms an explosive `NCl_(3)`. What is the mole ratio of `NH_(3)` and `Cl_(2)` required for this reaction?

A

`8:3`

B

`1:1`

C

`1:3`

D

`10:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(NH_(3),+,3Cl_(2),to,NCl_(3),+,HCl),("1 mole",,"3 moles",, "1 mole",,"3 moles"):}`
`therefore NH_(3):Cl_(2)=1:3`
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