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Diborane reacts with HCl in the present ...

Diborane reacts with HCl in the present of `AlCl_(3) and ` liberates

A

`H_(2)`

B

`Cl_(2)`

C

`BCl_(3)`

D

`Cl_(2) and BCl_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(("Diborane"))(B_(2)H_(6))+HCl overset(AlCl_(3)) to B_(2)H_(5)Cl+H_(2) uarr`
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