What are the oxidation number of nitrogen in `NH_(4)NO_(3) `?

Options

A. `+3,-5`
B. `-3,+5`
C. `+3,-6`
D. `+2,+2`

Answer

B

Explanation

The oxidation number of nitrogen in `NH_(4)NO_(2)` are
In `NH_(4)^(+),x+4=1,x=-3`
In `NO_(3)^(-),x+(-2xx3)=-1`
`x-6=-1`
`therefore x=+5`.