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Chlorine is passed into dilute cold KOH ...

Chlorine is passed into dilute cold KOH solution. What are the oxidation numbers of chlorine in the products formed ?

A

`-1,+5`

B

`-1,+3`

C

`+1,+7`

D

`-1,+1`

Text Solution

Verified by Experts

The correct Answer is:
D
The reaction is as follows,
`2KOH + Cl_(2) to KCl +KOCl +H_(2)O` Oxidation number of chlorine in KCl and KOCl is
`{:("In KCl","In KOCl"),((+1)+x=0,1-2+x=0),(thereforex=-1,therefore x=+1):}`
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