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tan[1/2"Sin"^(-1)(2a)/(1+a^(2))+1/2"Cos"...

`tan[1/2"Sin"^(-1)(2a)/(1+a^(2))+1/2"Cos"^(-1)(1-a^(2))/(1+a^(2))]=`

A

`1-a^(2)/(1+a^(2))`

B

`2a/(1+a^(2))`

C

`(1+a^(2))/(1-a^(2))`

D

`2a/1-a^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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