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In DeltaABC,a/cosA=b/cosB=c/cosC,ifb=2 t...

In `DeltaABC,a/cosA=b/cosB=c/cosC,ifb=2` then the area of the triangle is

A

`sqrt2`

B

`sqrt3`

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
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