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In a triangle ABC, C=90^@. Then (a^2-b^2...

In a triangle ABC, `C=90^@`. Then `(a^2-b^2)/(a^2+b^2)`=

A

sin (A+B)

B

sin (A-B)

C

cos (A+B)

D

cos (A-B)

Text Solution

Verified by Experts

The correct Answer is:
B
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