In Delta ABC, (r1+r2)(r2+r3)(r3+r1)=...

In `Delta ABC, (r_1+r_2)(r_2+r_3)(r_3+r_1)=`

A

`4Rs^2`

B

`4Rr^2`

C

R

D

0

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The correct Answer is:

A

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DIPTI PUBLICATION ( AP EAMET)-PROPERTIES OF TRIANGLES -EXERCISE 1B

In any triangle ABC, r1r2+r2r3+r3r1=
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In Delta ABC, (r1+r2)(r2+r3)(r3+r1)=
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In Delta ABC, 1/r1^2+1/r2^2+1/r3^2+1/r^2 =
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In Delta ABC, Delta^2/(a^2+b^2+c^2) {1/r1^2+1/r2^2+1/r3^2+1/r^2}=
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In Delta ABC, (1/r-1/r1)(1/r-1/r2)(1/r-1/r3)=
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In a triangle , if r1=2r2=3r3, then a/b+b/c+c/a=
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In Delta ABC, r+r2+r3-r1=
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In Delta ABC, r+r2+r3-r1=
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In Delta ABC, r+r2+r3-r1=
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IF in a Delta ABC, r3=r1+r2+r, then angle A+ angle B=
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In Delta ABC, r1^2+r2^2+r3^2+r^2=
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In Delta ABC, (ab-r1 r2)/r3=
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In Delta ABC, (r1 r+r2 r3)/(bc)=
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In Delta ABC, r3+ (r1 r2)/(r1+r2)=
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In DeltaABC,sqrt[[(rr1)/(r2r3)])=
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In Delta ABC, (r3+r1)sqrt[[(rr2)/(r3r1)])=
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In DeltaABC,r1r2sqrt[[(4R-r1-r2)/(r1+r2)])
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In DeltaABC,(r2(r3+r1))/sqrt(r1 r2+r2 r3+r3r1)=
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In DeltaABC,(b-c)/r1+(c-a)/r2+(a-b)/r3=
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