The point of intersection of the straigh...

The point of intersection of the straight lines `2x+3y+4=0, 6x-y+12=0` is

A

(2, -3)

B

(-2, 0)

C

(-2, -1)

D

(-2, 1)

Text Solution

Verified by Experts

The correct Answer is:

B

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Find the point of intersection of the lines 5x-3y-3=0,4x+y-1=0

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Knowledge Check

The vertical straight line passing through the point of intersection of the straight lines x-3y+1=0, 2x+5y-9=0 and at a distance of 2 units from the origin has the equation

A

`x-3y+1=0`

B

`x=2`

C

`y=1`

D

`3x+4y=10`

The perpendicular distance of the straight line 3x + 4y- 8 = 0 from the point of intersection of the lines 3x + 2y + 4 = 0, 2x + 5y -1=0 is

A

`11/5`units

B

`12/5`units

C

`8/5`units

D

`9/5`units

The perpendicular distance of the straight line 3x + 4y- 8 = 0 from the point of intersection of the lines 3x + 2y + 4 = 0, 2x + 5y -1=0 is

A

`11/5`units

B

`12/5`units

C

`8/5`units

D

`2`units

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The equation of the straight line which is perpendicular to the line 5x-2y =7 and passing through the point of intersection of the lines 2x + 3y-1 =0 and 3x + 4y -6 = 0 is

The equation of the line passing through the point of intersection of the lines 2x+3y-4=0, 3x-y+5=0 and the origin is

The equation of the line passing through the point of intersection of the lines 2x+3y+6=0, 3x-y-13 =0 and parallel to the line 3x-4y+5=0 is

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