Home
Class 12
MATHS
The ends of the base of an isoceles tria...

The ends of the base of an isoceles triangle are at (2a, 0) and (0, a). The equation of one side is `x=2a` . The equation of the other side is

A

`x+y=a`

B

`x+2y=a`

C

`x+2y=2a`

D

`2x+y=2a`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) (SET-1)|10 Videos

  • STRAIGHT LINES

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) (SET-2)|7 Videos

  • STRAIGHT LINES

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1A|119 Videos

  • SETS ( APPENDIX - 1)

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE|70 Videos

  • SYSTEM OF CIRLES

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SET-4 )|4 Videos

Similar Questions

Explore conceptually related problems

If the ends of the base of an isosceles triangle are at (2,0) and (0,1) , and the equaiton of one side is x=2 then the orthocenter of the triangle is

The extremites of the base of an isosceles triangle are (2,0) and (0,2). If the equation of one of the equal side is x=2, then the equaiton of other unequal side is

One vertex of an equilateral triangle is (2,3) and the equation of one side is x-y+5=0. Then the equation to other sides are

If 2x^(2)-5xy+2y^(2)=0 represents two equal sides of an isosceles triangle and the third side passes through (3,1) then equation of third side is

The base of an equilateral triangle x + y = 2 = 0 and opposite vertex is (2 , - 1). Find the equations of the remaining sides .

The equation to the base of a equilateral triangle is x+y=2 and one vertex is (2,-1). The length of the side is

Changing of term from one side of equation to other side is called ____.

The equation of the base of ann equilateral triangle is 3x-4y+15=0 and one vertex is (1,2). The length of the side is

DIPTI PUBLICATION ( AP EAMET)-STRAIGHT LINES -EXERCISE 1B
  1. Let P(-1,0), Q(0,0) and R(3,3sqrt(3)) be three points. The equation of...

    Text Solution

    |

  2. The base of an equilateral triangle x + y = 2 = 0 and opposite vertex...

    Text Solution

    |

  3. The ends of the base of an isoceles triangle are at (2a, 0) and (0, a)...

    Text Solution

    |

  4. The area of the triangle formed by the lines 2x+y-4=0, 3x+2y-5=0, x+y+...

    Text Solution

    |

  5. The line 3x+2y=24 meets the y-axis at A and the x-axis at B. The perp...

    Text Solution

    |

  6. The line 3x+2y=24 meets the y-axis at A and the x-axis at B. The perp...

    Text Solution

    |

  7. The are of the triangle formed by the y-axis, the line L passing throu...

    Text Solution

    |

  8. A line meets the coordinate axes at A and B such that the centroid of ...

    Text Solution

    |

  9. Let P(-1,0), Q(0,0) and R(3,3sqrt(3)) be three points. The equation of...

    Text Solution

    |

  10. In DeltaABC, if B = (1, 2), C = (5, 6) and the internal bisector of th...

    Text Solution

    |

  11. In a triangle ABC, if A-=(1,2) and the internal angle bisectors throug...

    Text Solution

    |

  12. The base of a triangle lies along the line x=a and is of length a. The...

    Text Solution

    |

  13. A(1, 0), B(0, 1) are two points. If P(x, y) is a point such that xy gt...

    Text Solution

    |

  14. The quadrilateral formed by the lines x+8y+37=0, 7x-6y+11=0, x+8y-87=0...

    Text Solution

    |

  15. The lines 2x+y=1, x+2y=1, 2x+y=3, x +2y=3 form

    Text Solution

    |

  16. The quadrilateral formed by the lines x-y+2=0, x+y=0, x-y-4=0, x+y-12=...

    Text Solution

    |

  17. The quadrilateral formed by the lines x+y-3=0, x-y+3=0, x+y+1=0, x-y-1...

    Text Solution

    |

  18. The quadrilateral formed by the lines sqrt(3)x+y=0,sqrt(3)y+x=0, sqrt(...

    Text Solution

    |

  19. The are of the quadrilateral formed by the lines x-y+2=0, x+y=0, x-y-4...

    Text Solution

    |

  20. A : The area of the parallelogram formed by 4x-7y-13=0, 8x-y-39=0, 4x-...

    Text Solution

    |