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(d)/(dx) {e ^(ax)sin (bx+c)}=...

`(d)/(dx) {e ^(ax)sin (bx+c)}=`

A

`e ^(ax) [a sin (bx +c) +b cos (bx+c)]`

B

`e ^(ax) [ a cos (bx + c ) + b sin (bx +c]`

C

`e ^(nx) [ a sin (bx +c) -b cos (bx +c)]`

D

`e ^(nx) [ a cos (bx + c )- b sin (bx +c)]`

Text Solution

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The correct Answer is:
A
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