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(1)/(n!) +(1)/((n+1)!)+(1)/((n+2)!)=...

`(1)/(n!) +(1)/((n+1)!)+(1)/((n+2)!)=`

A

`(n^2 +n+11)/((n-1)!)`

B

`(n^2 +4n +5 )/((n+2)!)`

C

`(n^2+6n+3)/( (n+1)!)`

D

none

Text Solution

Verified by Experts

The correct Answer is:
B
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