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The number of arrangements that can be...

The number of arrangements that can be made by taking all from 6 red balls , 4 blue balls and 3 white balls of same size is

A

`(15 !)/(7!5!3!)`

B

`(12!)/(6!5!3!)`

C

`(16!)/(4!3!2!)`

D

`(13!)/(6!4!3!)`

Text Solution

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The correct Answer is:
D
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DIPTI PUBLICATION ( AP EAMET)-PERMUTATIONS & COMBINATIONS-EXERCISE 1A (PERMUTATIONS )
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