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Out of (2n+1) tickets consecutively numb...

Out of (2n+1) tickets consecutively numbered , three are drawn at random . The chance that the numbers on them are in A.P is

A

`(n)/(n^(2)-1)`

B

`(3n)/(n^(2)-1)`

C

`(3n)/(4n^(2)-1)`

D

`(3n)/(4n^(2)+2n-1)`

Text Solution

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The correct Answer is:
C
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