Home
Class 12
MATHS
A is one of 6 horses entered for a race ...

A is one of 6 horses entered for a race and is to be ridden by one of two jockeys P and Q. It is 2 to 1 that P rides A, in which case all the horses are likely to win. If Q rides A, his chace is tribled . The odds favour of his winning are

A

5/13

B

18/5

C

13/18

D

5/18

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) SET-1|6 Videos

  • PROBABILITY

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) SET-2|8 Videos

  • PROBABILITY

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE-1B|62 Videos

  • PERMUTATIONS & COMBINATIONS

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 ( SPECIAL TYPE QUESTIONS ) SET -4|10 Videos

  • PRODUCTS OF VECTORS

    DIPTI PUBLICATION ( AP EAMET)|Exercise Exercise 2 (Special Type Questions) SET -D|14 Videos

Similar Questions

Explore conceptually related problems

A is one of 5 horses that entered the race and for it to be rided by one of the two jokeys P & Q and odds in favour of P rides it is 2 to 1. If P rides, A, all the horses are likely to win. If Q rides A, A' s chance of winning is tripled. The odds in favour of A's winning is

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) B. What is the number of one long and one short pairs?

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) A. what is the number of long strip paris?

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) C. What is the number of short strip pairs?

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) D. What is the percentage of each type? also find their ratios.

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) E. What can you coclude from this game?

An orbital is designated by certain values of first three quantum numbers (n, l and m) and according to Pauli.s exclusion principle, no two electrons in a atom can have all the for quantum numbers equal. N, l and m denote size, shape and orientation of the orbital. The permissible values of n are 1,2,3.... prop while that of 1 are all possible integral values from 0 to n-n. Orbitals with same values of n and 1 but different values of m (where m can have any integral values from 1 to +1 including zero) are of equal energy and are called degenerate orbitals. However degeneracy is destroyed in homogeneous external magnetic field due to different extent of interaction between the applied field and internal electronic magnet of different orbitals differing in orientations. In octahedral magnetic field external magnetic field as oriented along axes while in tetrahedral field the applied field actas more in between the axes than that on the axes themselves. For 1=0, 1,2,3,...., the states (called sub-shells) are denoted by the symbol s,p,d,f.....respectively. After f, the subshells are denoted by letters alphabetically 1 determines orbital angular motion (L) of electron as L = sqrt(l(l+1))(h)/(2pi) ON the other hand, m determines Z-component of orbital angular momentum as L_(Z) = m((h)/(2pi)) Hund.s rule states that in degenerate orbitals electrons do not pair up unless and until each each orbitals has got an electron with parallesl spins Besides orbital motion,an electron also posses spin-motion. Spin may be clockwise and anticloskwise. Both these spin motions are called two spins states of electrons characterized by spin Q.N (s) : s = +(1)/(2) and = -(1)/(2) respectively The sum of spin Q.N. of all the electrons is called total spin(s) and 2s+1 is called spin multiplicity of the configuration as a whole. The spin angular momentum of an electron is written as L_(s) = sqrt(s(s+1))(h)/(2pi) According to Hund.s rule, the distribution of electron within the various orbitals of a given sub-shell is one which is associated with

There is a pair of bean-shaped organs P in the human body towards the back just above the waist. A waste product Q formed by the decomposition of unused proteins in liver is brought into organ P through blood by an artery R The numerous tiny filters S present in organ P clean the dirty blood goes into circulation through a vein T . The waste substance Q other waste salts and excess water form a yellowish liquid U which goes from organ P into a bag like structure V through two tubes W This liquid is then thrown out of the body through a tube X .Name (1) artery R and (2) vein T

DIPTI PUBLICATION ( AP EAMET)-PROBABILITY-EXERCISE-1C
  1. A bag contains 5 red , 3 black ball, and another bag contains 4 red an...

    Text Solution

    |

  2. A bag contains 16 coins of which two are counterfeit with heads on bot...

    Text Solution

    |

  3. A is one of 6 horses entered for a race and is to be ridden by one of ...

    Text Solution

    |

  4. A is one of 6 horses entered for a race and is to be ridden by one of ...

    Text Solution

    |

  5. A bag contains 6 white and 4 black balls.A fair die is rolled and a nu...

    Text Solution

    |

  6. A bag contains 2n coins out of which n-1 are unfair with heads on both...

    Text Solution

    |

  7. A letter is known to have come either from LONDON or CLIFTON, on the p...

    Text Solution

    |

  8. A bag contains four balls. 3 white balls and 1 black ball.2 balls are...

    Text Solution

    |

  9. A bag contains six balls. Two balls are drawn and found them to be red...

    Text Solution

    |

  10. An urn contains 5 white and 3 black balls and 4 balls are drawn at ran...

    Text Solution

    |

  11. Three boxes numbered, I, II, III contain balls as follows {:(,"White...

    Text Solution

    |

  12. A bag A contains 2 white and 3 red balls and a bag B contains 4 white ...

    Text Solution

    |

  13. Fpr L=1,2,3 the box Bk contains k red balls and (k+1) white balls . Le...

    Text Solution

    |

  14. Box A contains 2 black and 3 red balls, while box B contains 3 black ...

    Text Solution

    |

  15. A ,B ,C are there routes from the house to the office. On any day, the...

    Text Solution

    |

  16. A man is known to speak the truth 3 out of 4 times. He throws a die an...

    Text Solution

    |

  17. A man speaks truth in 60% cases. He throws a die and reports that it i...

    Text Solution

    |

  18. A man is known to speack the truth 2 out of 3 times . He throws a die ...

    Text Solution

    |

  19. In an entrance test there are multiple choice questions. There are fou...

    Text Solution

    |

  20. In a certain colleage, 4% of men and 1% of women are taller than 1.8m....

    Text Solution

    |