1+(2)/(1!)+(3)/(2!)+(4)/(3!)+....=...

`1+(2)/(1!)+(3)/(2!)+(4)/(3!)+....=`

`2e`

`e^(-1)`

`e^(-1)//2`

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The correct Answer is:

EXPONENTIAL SERIES & LOGARITHMIC SERIES (APPENDIX-1)
DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1B|70 Videos
EXPONENTIAL SERIES & LOGARITHMIC SERIES (APPENDIX-1)
DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 1|6 Videos
EXPONENTIAL SERIES & LOGARITHMIC SERIES (APPENDIX-1)
DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 4|5 Videos
ELLIPSE
DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 2|1 Videos
FUNCTIONS
DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS)|7 Videos

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(1)/(3!)+(2)/(5!)+(3)/(7!)+....=
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1+(2)/(1!)+(3)/(2!)+(4)/(3!)+....=
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(3)/(2!)+(5)/(3!)+(7)/(4!)+(9)/(5!)+....=
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1+(4)/(2!)+(7)/(3!)+(10)/(4!)+....=
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underset(n=1)overset(oo)Sigma(2n)/((2n+1)!)=
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underset(n=1)overset(oo)sum(n^(2))/((n+1)!)=
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underset(n=1)overset(oo)Sigma(2n^(2)+n+1)/(n!)=
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(1+(1)/(2!)+(1)/(4!)+(1)/(6!)+....)^(2)-(1+(1)/(3!)+(1)/(5!)+(1)/(7!)+...
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(1+(a^(2)x^(2))/(2!)+(a^(4)x^(4))/(4!)+....)^(2)-(ax+(a^(3)x^(3))/(3!)...
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(1+(2^(2))/(2!)+(2^(4))/(3!)+(2^(6))/(4!)+....)/(1+(1)/(2!)+(2)/(3!)+(...
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(1+(1)/(3!)+(1)/(5!)+....)/(1+(1)/(2!)+(1)/(4!)+....)=
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((1)/(2!)+(1)/(4!)+(1)/(6!)+....)/(1+(1)/(3!)+(1)/(5!)+....)=
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(1)/(2)-(1)/(3(1!))+(1)/(4(2!))-(1)/(5(3!))+....=
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(1)/(1!)+(1+2)/(2!)+(1+2+2^(2))/(3!)+....=
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(1)/(1!)+(1+3)/(2!)+(1+3+3^(2))/(3!)+....=
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(1)/(2!)+(1+2)/(3!)+(1+2+3)/(4!)+....
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(2)/(2!)+(2+4)/(3!)+(2+4+6)/(4!)+....=
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(1)/(1!)+(1+3)/(2!)+(1+3+3^(2))/(3!)+....=
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