(1)/(2!)+(1+2)/(3!)+(1+2+3)/(4!)+.......

`(1)/(2!)+(1+2)/(3!)+(1+2+3)/(4!)+....`

`e//2`

`1//e`

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The correct Answer is:

EXPONENTIAL SERIES & LOGARITHMIC SERIES (APPENDIX-1)
DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1B|70 Videos
EXPONENTIAL SERIES & LOGARITHMIC SERIES (APPENDIX-1)
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EXPONENTIAL SERIES & LOGARITHMIC SERIES (APPENDIX-1)
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ELLIPSE
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FUNCTIONS
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(1)/(1!)+(1+3)/(2!)+(1+3+3^(2))/(3!)+....=
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(1)/(2!)+(1+2)/(3!)+(1+2+3)/(4!)+....
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(2)/(2!)+(2+4)/(3!)+(2+4+6)/(4!)+....=
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(1)/(1!)+(1+3)/(2!)+(1+3+3^(2))/(3!)+....=
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1^(2)+(2^(2))/(2!)+(3^(2))/(3!)+(4^(2))/(4!)+....=
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(1^(2))/(2!)+(2^(2))/(3!)+(3^(2))/(4!)+....=
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(1^(2))/(1!)+(1^(2)+2^(2))/(2!)+(1^(2)+2^(2)+3^(2))/(3!)+....=
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(1^(2).2)/(1!)+(2^(2).3)/(2!)+(3^(2).4)/(3!)+....=
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(1^(2).2^(2))/(1!)+(2^(2).3^(2))/(2!)+(3^(2).4^(2))/(3!)+....=
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underset(n=1)overset(oo)sum.^(n)C(0)+.^(n)C(1)+underset(.^(n)P(n))(.^(...
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1-(x^(2))/(2!)+(x^(4))/(4!)-(x^(6))/(6!)+....=
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1+(1)/(2!)+(1.3)/(4!)+(1.3.5)/(6!)+...=
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If S=(1)/(1.2)+(1.3)/(1.2.3.4)+(1.3.5)/(1.2.3.4.5.6)+...."to "oo, then...
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The sum of the series 1+(1)/(4.2!)+(1)/(16.4!)+(1)/(64.6!)+...oo is
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1+(2x)/(1!)+(3x^(2))/(2!)+(4x^(2))/(3!)+....=
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1.2+(2.3)/(1!)x+(3.4)/(2!)x^(2)+....=
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