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For a particular reaction, the rate cons...

For a particular reaction, the rate constant becomes double on increasing temperature from `27^(@)C` to `37^(@)C.` Calculate the approximate activation energy (in kcal `mol^(1) R = 2 cal mol^(-1)K^(-1))`

A

1289

B

12.89

C

1.28

D

53.41

Text Solution

Verified by Experts

The correct Answer is:
B
We know that
`log (k_(2))/(k_(1))= (E_(a))/(2. 303R) xx (10)/(93xx1000)`
`E_(a)= 0. 3010xx2xx93xx100xx2. 303`
`E_(a)= 5598. 6 " cal"xx2.303`
`E_(a)= 56xx 2. 303=12. 89 " kcal / mol"`
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