The nitrogen gas pressure inside a container of volume `2.6 cm^(3)` is `2.3` atm at `27^(@)C` . The approximate number of moles of nitrogen present in the container is
[ `R=0.0821` L atm `"mol"^(1)K^(-1)` ]

Options

A. `4xx10^(-3)`
B. `1.7xx10^(-4)`
C. `4xx10^(-4)`
D. `2xx10^(-4)`

Answer

D

Explanation

Given,
Pressure of `N_(2)` gas `=2.3` atm
Volume `=2.6 cm^(3)`
`=2.6xx10^(-3)L`
Temperature`=27^(@)C+273`
`=300` K
Gas constant (R) `=0.0821` L atm `"mol"^(-1)K^(-1)`
From, ideal gas equation
`pV=nRT`
`n=(pV)/(RT)`
`n=(2.3 "atm"xx2.6xx10^(-3)L)/(0.0821"L atm mol"^(-1)//Kxx300K)`
`n=2xx10^(-4)` mol