`X e F_(4)` is square planar while `X eF_(6)` has a distorted octahedral structure. What is the correct explanation for this observation ?

Options

A. Both molecules have one lone pair of electrons
B. Both molecules have two lone pairs of electrons
C. `XeF_(4)` does not have any lone pair of electrons,
`XeF_(6)` has one lone pair of electrons on Xe
D. `XeF_(4)` has two lone pairs of electrons on `Xe, XeF_(6)` has one lone pair of electrons on Xe

Answer

D

Explanation

`XeF_(4)` is square planar and `sp^(3)d^(2)`-hybridised.

`4 sigma + 2lp=6`-hybrid orbital
`sp^(3)d^(2)`-hybridisation
`X eF_(6)` has distorted octahedral structure and
`sp^(3)d^(3)`-hybridised.

`6 sigma+1lp=7`-hybrid orbital
(`sp^(3)d^(3)`) (distorted octahedral )
Thus, option (d) is correct.