In a Young's d
ouble slit experiment, a monochromatic light of wavelenght 600 nm is used. If the two slits are covered bt transparent sheets of thickness 0.132 mm and 0.1 mm of refractive index 1.5, then the number of fringes that will shift due to introdiction of the sheets are

Options

A. 27
B. 40
C. 60
D. 80

Explanation

(No option is matching)
Number of fringes shift due to extra path difference caused by transparent slab is
`n=((mu - 1)t)/(lambda)`
So, when two plates of thickness `t_(1) and t_(2)` are placed infront of slits, then shift is
`n=n_(2)-n_(1)=((mu - 1)(t_(2) - t_(1)))/(lambda)`
`=((1.5-1)(0.132-0.1)xx10^(-3))/(600xx10^(-9))`
`=(0.5xx0.032xx10^(6))/(600)=27 ` fringes