In a juction transistor, the collector current changes by 6.8 mA, if the emitter current is changed by 7 mA. For such transistor,the current amplification factor is

Options

A. 30
B. 34
C. 40
D. 45

Answer

B

Explanation

Given,`Delta1_(c)= 6.8` mA
`Delta1_(E)= 7` mA
So, `Delta1_(B)= 0.2` mA
`because` Current amplification is `gt` 1
So, it must be CE configuration
Amplification factor,`beta = (DeltaI_(c))/(DeltaI_(B))=(6.8 mA)/(0.2 mA)`
`rArr beta = 34`