The wavelength of the radiation emitted by a black body is 1 mm and Wien's constant is `3xx10^(-3)` mK. Then the temperature of the black body will be

Options

A. 3 K
B. 30 K
C. 300 K
D. 3000 K

Answer

A

Explanation

As we know temperature of a black body is given by,
`lambdaT=b` ( Wien.s displacement law )
Where, wavelength of the radiation,
`lambda=1mm=1xx10^(-3)m`
Wien.s constant , `b=3xx10^(-3)`mK
`rArr T=b/lambda= (3xx10^(-3))/(1xx10^(-3))=3K`
So, the correct option is (a).