Collision takes place between two solid spheres denoted as 1 and 2. The initial velocities of the spheres are `u_1` = 3 m/s and` u_2` = 1.5 m/s and the final velocities are `v_1` = 2.5 m/s and `v_2` = 3.5 m/s. The coefficient of restitution between the materials of the spheres is nearly

Options

A. 0.67
B. 0.78
C. 0.83
D. 0.96

Answer

A

Explanation

Coefficient of restitution
e = Relative velocity of separation / Relative velocity of approach
`rArr e = (v_2 -v_1)/(u_1 - u_2) = (3.5- 2.5)/(3- 1.5) = (1)/(1.5) = 2/3 = 0.67`