Consider an electron revolving in a circular orbit of hydrogen atom, whose quantum number is n=2 The velocity of the electron in that orbit is

Options

A. `1.1 xx 10^6 m//s`
B. `2.2 xx 10^7 m//s`
C. `4.4 xx 10^6 m//s `
D. `2.2 xx 10^5 m//s `

Answer

A

Explanation

Velocity of electron of H - atom in nth orbit is
`V_n = (v_1)/(n) = (2.2 xx 10^6)/(2) = 1.1 xx 10^6 ms^(-1)`