A cricket player can throw a ball with an initial speed of 30 m/s. What is the maximum range of the player can throw the ball? Neglect air reistance. [Take g =`10 m//s^(2)`]

Options

A. 100m
B. 90 m
C. 80 m
D. `90 sqrt2m`

Answer

B

Explanation

Maximum range occurs, when angle of throw `theta = 45^(@)`
Also, range maximum `= (u^(2) sin 2 theta)/(g)|_(theta = 45^(@)`
`= (u^(2))/(g) = (900)/(10) = 90 m`