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Ifintphi(x)dx=Psi(x)," then "int(phi(@)h...

If`intphi(x)dx=Psi(x)," then "int(phi_(@)h)(x)h(x)h'(x)dx=`

A

`(phi_(@)h)(x)phi'(x)-int(phi_(@)h)(x)h'(x)dx+c`

B

`(Psi_(@)h)(x)h(x)-int(Psi_@h)(x)h'(x)dx+c`

C

`(Psi_@h)(x)phi(x)-int(Psi_@h)(x)phi'(x)dx+c`

D

`(Psi_@Phi)(x)h(x)-int(Psi_@phi)(x)h'(x) dx +c`

Text Solution

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The correct Answer is:
B
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