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A person buys eight packets of TIDE dete...

A person buys eight packets of TIDE detergent. Eachpacket contains one coupon, which bears one of the let-ters of the word TIDE. If he shows all the letters of theword TIDE, he gets one free packet. If he gets exactlyone free packet, then the number of different possiblecombinations of the coupons is

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A person buys twelve packets of VANISH degergent. Each packet contains one coupon, which bears one the letters of the word VANISH. If he shows all the letters of the word VANISH, he gets one free packet. If he gets exactly one free packet, then the number of different possible combinations of the coupon is (a) ^18 C_6-^(17)C_6 (b) ^11 C_5 -1 (c) ^17 C_5 (d) 461

A shoping mall is running a scheme: Each packet of detergent SURF contains a coupon which bears letter of the word SURF, if a person buys at least four packets of detergent SURF, and produce all the letters of the word SURF, then he gets one free packet of detergent. If a person buys 8 such packets at a time, then the number of different combinations of coupon he has is

A shoping mall is running a scheme: Each packet of detergent SURF contains a coupon which bears letter of the word SURF, if a person buys at least four packets of detergent SURF, and produce all the letters of the word SURF, then he gets one free packet of detergent. If person buys 8 such packets, then the probability that he gets exactly one free packets is

A shoping mall is running a scheme: Each packet of detergent SURF contains a coupon which bears letter of the word SURF, if a person buys at least four packets of detergent SURF, and produce all the letters of the word SURF, then he gets one free packet of detergent. If a person buys 8 such packets, then the probability that he gets two free packets is

The English alphabet is categorised into 5 groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus, the first group would have letters A, B,C and D, the second E, F, G and H, and so on. These groups are assigned values as 10 for the first, 20 for the second, and so on, up to 50 the last. Every letter in a particular group will have the same value of the group when used to form words. The value of each letter should add up to compute the value of the word. If the word has letters only from the same group, the value of the word would be the value of the letter multiplied by the number of letters in the word. However, if the letters in a word are from different groups, the value of the first letter of the word and any other letter of that group will be the same as that of its group, but that of the subsequent letter will he ‘double’ as much as the value of its group. For example: The value of ‘CAB’ will be 30 (i.e. 10 + 10 + 10 ) as all the three letters are from the first group, each one having a value of 10. The value of ‘BUT’ will be 10 + (50*2) + (40*2)= 190 The value of ‘JUNK’ will be 30 + (50*2) + 30 + 30 = 190 . Now, find out the value of each word in the following questions: SPORT 1) 200 2) 360 3) 380 4) 250 5) None of these

The English alphabet is categorised into 5 groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus, the first group would have letters A, B,C and D, the second E, F, G and H, and so on. These groups are assigned values as 10 for the first, 20 for the second, and so on, up to 50 the last. Every letter in a particular group will have the same value of the group when used to form words. The value of each letter should add up to compute the value of the word. If the word has letters only from the same group, the value of the word would be the value of the letter multiplied by the number of letters in the word. However, if the letters in a word are from different groups, the value of the first letter of the word and any other letter of that group will be the same as that of its group, but that of the subsequent letter will he ‘double’ as much as the value of its group. For example: The value of ‘CAB’ will be 30 (i.e. 10 + 10 + 10 ) as all the three letters are from the first group, each one having a value of 10. The value of ‘BUT’ will be 10 + (50*2) + (40*2)= 190 The value of ‘JUNK’ will be 30 + (50*2) + 30 + 30 = 190 . Now, find out the value of each word in the following questions: SHOP 1) 70 2) 120 3) 130 4) 140 5) None of these

The English alphabet is categorised into 5 groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus, the first group would have letters A, B,C and D, the second E, F, G and H, and so on. These groups are assigned values as 10 for the first, 20 for the second, and so on, up to 50 the last. Every letter in a particular group will have the same value of the group when used to form words. The value of each letter should add up to compute the value of the word. If the word has letters only from the same group, the value of the word would be the value of the letter multiplied by the number of letters in the word. However, if the letters in a word are from different groups, the value of the first letter of the word and any other letter of that group will be the same as that of its group, but that of the subsequent letter will he ‘double’ as much as the value of its group. For example: The value of ‘CAB’ will be 30 (i.e. 10 + 10 + 10 ) as all the three letters are from the first group, each one having a value of 10. The value of ‘BUT’ will be 10 + (50*2) + (40*2)= 190 The value of ‘JUNK’ will be 30 + (50*2) + 30 + 30 = 190 . Now, find out the value of each word in the following questions: HIGH 1) 40 2) 60 3) 70 4) 80 5) None of these

A purse contains two coins of which one is two headed coin and the other is a fair con. A person selects one of the coins at random and tosses. If he gets head, the tosses the other coin, otherwise he tosses the same coin. It is given that he got head in the second toss. The probability that his first selection is a fair coin and getting head is

In a multiple choice question, there are five alternative answers of which one or more than one are correct. A candidate will get marks on the question, if he ticks all the correct answers. If he decides to tick answer all random, then the least number of choices should he be allowed, so that the probability of his getting marks on the question exceeds (1)/(8) is

Eight friends H, I, J, K, L, M, N and O are sitting in a row facing north. All of them like different colours - Red, Pink, Orange, Green, Yellow, Black, Violet and Blue. There is only 1 person between J and one who likes Violet. N is neither an immediate neighbour of J nor he likes Green.H sits fourth to the left of the one who likes Violet but she does not like pink. The person who likes Black is sits third to the right of the one who likes Green and sits on the immediate right of H. The one who likes Green sits at one of the extreme ends of the row. I does not like Green. M is an immediate neighbour of both N and J. O sits at one of the extreme end of the row but he does not like green. The one who likes Blue sits second to the right of the one who likes Orange. The one who likes Black and Pink are immediate neighbours. L sits third to the left of J and likes yellow. There is only one person sitting between the one who likes yellow and black . N like which of the following colour ?