" As If "sec theta+tan theta=x," then "sec theta=

If sec theta+tan theta=x, then sec theta=(a)(x^(2)+1)/(x) (b) (x^(2)+1)/(2x)(c)(x^(2)-1)/(2x) (d) (x^(2)-1)/(x)

If sec theta + tan theta = 4 , then sec theta- tan theta =?

If sec theta + tan theta = 12.5 , then sec theta - tan theta = ?

If sec theta + tan theta=(4)/(3) , then sec theta tan theta =_______

If sec theta+tan theta=2 , then sec theta-tan theta = ?

If sec theta - tan theta = x , show that sec theta = 1/2 (x +1/x) and tan theta = 1/2 (1/x -x) .

If theta is eliminated from the equations a sec theta-x tan theta=y" and "b sec theta+y tan theta=x (a and b are constants), then :

(5) sec theta+tan theta=7 then sec theta-tan theta=?