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[(cos3 theta)/(2cos2 theta-1)=(1)/(2)" i...

[(cos3 theta)/(2cos2 theta-1)=(1)/(2)" if "(n in1)],[[" (A) "theta=n pi+pi/3," (B) "theta=2n pi+-pi/3],[" (C) "theta=2n pi+-pi/6," (D) "theta=n pi+pi6]]

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