[" at real numbers wa that "(a^(2)+b^(2)+c^(4))p^(2)-2(ab+bc+a)],[" Bilp of "C;GPquad " D) ACP? "]

If a,b,c,d and p are distinct non -zero real numbers such that : ( a^(2) + b^(2) +c^(2))p^(2) - 2 ( ab + bc + cd) p + ( b^(2) + c^(2) + d^(2)) le 0 , then a,b,c,d :

if a,b, c, d and p are distinct real number such that (a^(2) + b^(2) + c^(2))p^(2) - 2p (ab + bc + cd) + (b^(2) + c^(2) + d^(2)) lt= 0 then a, b, c, d are in

if a,b, c, d and p are distinct real number such that (a^(2) + b^(2) + c^(2))p^(2) - 2p (ab + bc + cd) + (b^(2) + c^(2) + d^(2)) lt 0 then a, b, c, d are in

Let a,b,c,d and p be any non zero distinct real numbers such that (a^(2) + b^(2) + c^(2))p^(2) - 2(ab+bc+cd)p+ (b^(2) + c^(2) + d^(2))=0 . Then :

If a,b,c,d are such unequal real numbers that (a^(2)+b^(2)+c^(2))p^(2)-2 (ab+bc+cd) p+ (b^(2)+c^(2)+d^(2)) le 0 then a,b,c, d are in -

If a,b,c,d and p are different real numbers such that: (a^(2)+b^(2)+c^(2))p^(I2)-2(ab+bc+cd)p+(b^(2)+c^(2)+d^(2))<=0 ,then show that a,b,c and d are in G.P.

If a,b,c,d and p are different real numbers such that (a^(2)+b^(2)+c^(2))p^(2)-2(ab+bc+cd)p+(b^(2)+c^(2)+d^(2))<=0 ,then show that a,b,c and d are in G.P.

If a,b,c,d and p are distinct real numbers such that (a^(2)+b^(2)+c^(2))p^(2)-2(ab+bc+cd)p+(b^(2)+c^(2)+d^(2))<=0 then prove that a,b,c,d are in G.P.

If a,b,c,d and p are distinct real numbers such that (1987,2M)(a^(2)+b^(2)+c^(2))p^(2)-2(ab+bc+cd)P+(b^(2)+c^(2)+d^(2))>=0, then a,b,c,d are in AP(b) are in GP are in HP(d) satisfy ab=cd