(a+b)-i(3a+2b)=5+2i

If (a+b)+i(a-b)=2-3i find a\ a n d\ bdot

Express the following in the form of a + ib, where a, b in R , i = sqrt-1 . State the value of a and b. (3 + 2i) / (2 - 5i) + (3 - 2i) / (2 + 5i)

If a and b are vectors such that |a+b|=sqrt(29) and a xx(2i+3j+4k)=(2i+3j+4k)xx b, then a possivalue of (a+b)*(-7i+2j+3k) is

If a = 2i - 3j - k, b = I + 4j - 2k then (a + b) xx (a - b) =

I : If a = i + 4j, b = 2i - 3j, c = 5i + 9j then c = 3a + b II : If a = 3i - 6j + 2k then the length of the vector is 3.

Multiply (i) (a+7) and (b-5) (ii) (a^2+2b^2) and (5a-3b)

Multiply (i) (a+7) and (b-5) (ii) (a^(2)+2b^(2)) and (5a-3b)