किसी अभिक्रिया के लिये सक्रियण ऊर्जा का मान दोगुना है। जब तापक्रम 300 K से 310 तक बढ़ता है, तब दर है

Options

A. `50.6mol^(-1)`
B. `53.6KJmol^(-1)`
C. `56.6mol^(-1)`
D. `59.6KJmol^(-1)`

Answer

(b)

Explanation

`log10(k_(2))/(k_(1))=(E_(a))/(2.303R)[(1)/(t_(1))-(1)/(T_(2))]`
`k_(2)=2k_(1)` `"log"_(10)(2k_(1))/(k_(1))=(E_(a))/(2.303xx8.314)[(1)/(300)-(1)/(310)]`
`log2=(E_(a))/(2.303xx8.314)[(310-300)/(300xx310)]`
`0.0310=(E_(a))/(2.303xx8.314)((10)/(93000))`
`E_(a)=(0.3010xx2.303xx8.314xx93000)/(10)`
`E_(a)=53.6kJ mol^(-1)`