" 4."|x-1|+|2x-3|=|3x-4|

solve for x, (x-1)+(2x-3)=(3x-4)

The transformed equation with integer co-effcients whose roots are multipled by some constant of those of x^4 -1/2 x^3 +3/4 x^2 -5/4 x+(1)/(16 )=0 is

If (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) and x ne 1/3 then x=? यदि (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) है तथा x ne 1/3 है, तो x=?

Solve for : x :(x-1)/(x-2)+(x-3)/(x-4)=3 1/3,x!=2,4

Solve for x : (x-1)/(x-2)+(x-3)/(x-4)=3 1/3;\ \ x!=2,\ 4

Solve for :x:(x-1)/(x-2)+(x-3)/(x-4)=3(1)/(3),x!=2,4

Solve for x:(x-1)/(x-2)+(x-3)/(x-4)=3(1)/(3);x!=2,4

What is the HCF of the polynomials x^4-3x+2,x^3-3x^2+3x-1 and x^4-1

"If "f(x)=(x-1)^(4)(x-2)^(3)(x-3)^(2)(x-4), then the value of f'''(1)+f''(2)+f'(3)+f'(4) equals