[" The differential equation "2xydy=(x^(2)+y^(2)+1)dx],[" determines "]

The differential equation 2xy dy = (x^2 + y^2 + 1) dx determines

Solve the differential equation (x^(2)+y^(2))dx+2xydy=0

Solve the following differential equations 2xydy=(y^(2)-x^(2))dx

Solve the following differential equations 2xydy=(y^(2)-x^(2))dx

Solve the differential equations. (dy)/(dx)=(x^(2))/(1+y^(2))

For the differential equation xydy/dx = (x + 2) (y +2) , find the solution curve passing through the point (1, -1) .

Let y=f(x) be function satisfying the differential equation (y^(2)x-y^(2))dx-xydy-0 and y(1)=e then the range of the function f(x) is: