f:R rarr R,f(x)=x|x|" is "

If R is the set of real numbers prove that a function f:R rarr R,f(x)=e^(x),x in R is one to one mapping.

Function f : R rarr R , f(x) = x + |x| , is

Function f : R rarr R , f(x) = x + |x| , is

If f:R rarr R,f(x)=x^(3)+x, then f is

If f:R rarr R,f(x)=x+sin x, then value of int_(0)^( pi)(f^(-1)(x))dx equals

Function is said to be onto if range is same as co - domain otherwise it is into. Function is said to be one - one if for all x_(1) ne x_(2) rArr f(x_(1)) ne f(x_(2)) otherwise it is many one. Function f:R rarr R, f(x)=x^(2)+x , is

Show that f: R rarr R , f(x) = x/(x^(2)+1) is not one one and onto function.

f:R rarr R; f(x)=(x^2-x) then fof(x) is

Which of the following function is surjective but not injective.(a) f:R rarr R,f(x)=x^(4)+2x^(3)-x^(2)+1(b)f:R rarr R,f(x)=x^(2)+x+1(c)f:R rarr R^(+),f(x)=sqrt(x^(2)+1)(d)f:R rarr R,f(x)=x^(3)+2x^(2)-x+1

Let f:R rarr R,f(x)=x^(3)+x-1. Find the solution of f(x)=f^(-1)x