Home
Class 11
BIOLOGY
Assertion: In green plants H(2)O is the ...

Assertion: In green plants `H_(2)O` is the hydrogen donor and is oxidised to `O_(2)`
Reason: In the purple and green sulphur bacteria, the oxidation product is sulphur or sulphate depending on the organism and not `O_(2)`.

A

If both assertion and reason are true and the reason 1s the correct explanation of the assertion.

B

If both assertion and reason are true but reason is not the correct explanation of the assertion.

C

If assertion is true but reason is false.

D

If both assertion and reason are false.

Text Solution

Verified by Experts

The correct Answer is:
B

In green plants `H_(2)O` is the hydrogen donor and is oxidised to `O_(2)`.
In the purple and green sulphur bacteria, the oxidation product is sulphur or sulphate depending on the organism and not `O_(2)`
Promotional Banner

Topper's Solved these Questions

  • PHOTOSYNTHESIS IN HIGHER PLANTS

    A2Z|Exercise SECTION C : Previous Years' Examination Questions (NEET/AIPMT Questions)|80 Videos
  • PHOTOSYNTHESIS IN HIGHER PLANTS

    A2Z|Exercise SECTION C : Previous Years' Examination Questions (AIIMS QUESTIONS )|13 Videos
  • PHOTOSYNTHESIS IN HIGHER PLANTS

    A2Z|Exercise Section A : Topicwise Questions Topic 3 : Dark Reaction (the Calvin Cycle)|27 Videos
  • NEURAL CONTROL AND COORDINATION

    A2Z|Exercise Section D : Chapter-end Test|50 Videos
  • PLANT GROWTH AND DEVELOPMENT

    A2Z|Exercise Section D : Chapter-end Test|50 Videos

Similar Questions

Explore conceptually related problems

In purple and green sulphur bacteria, the hydrogen donor is

In green plants photosynthesis what is the hydrogen donor and gets oxidised to O_(2) ?

H_(2)O is oxidised to O_(2) by :

Calculate the oxidation number of sulphur in S_2O_8^(2-) ion.

The oxidation number of sulphur in Na_2S_4O_6 is .

The average oxidation state of sulphur in Na_2S_4O_6 is

Who, after conducting experiments on purple and green sulphur bacteria, inferred that O_(2) evolved during photosynthesis comes from H_(2)O not from CO_(2) ?

The oxidation number of sulphur is Na_(2)S_(2)O_(4) is

The oxidation number of sulphur in Na_(2)S_(4)O_(6) is