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" 13."tan^(-1)2-tan^(-1)1=tan^(-1)(1)/(3...

" 13."tan^(-1)2-tan^(-1)1=tan^(-1)(1)/(3)

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tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

Pove that i) tan^(-1)1/2+tan^(-1)2/11=tan^(-1)3/4 ii) tan^(-1)2/11+tan^(-1)7/24=tan^(-1)1/2 iii) tan^(-1)1+tan^(-1)1/2+tan^(-1)1/3=pi/2 iv) 2tan^(-1)1/3+tan^(-1)/17=pi/4 v) tan^(-1)2-tan^(-1)1=tan^(-1)1/3 vi) tan^(-1)+tan^(-1)2+tan^(-1)3=pi vii) tan^(-1)1/2+tan^(-1)1/5+tan^(-1)1/8=pi/4 viii) tan^(-1)1/4+tan^(-1)2/9=1/2tan^(-1)4/3

tan^(-1)1+tan^(-1)2+tan^(-1)3=

tan^(-1)1+tan^(-1)2+tan^(-1)3=

Prove that 2tan^(-1)(1/2)-tan^(-1)(1/4)=tan^(-1)(13/16)

Prove that: tan^(-1)(1)/(7)+tan^(-1)(1)/(13)=tan^(-1)(2)/(9)tan^(-1)+tan^(-1)(1)/(5)+tan^(-1)(1)/(8)=(pi)/(4)tan^(-1)(3)/(4)+tan^(-1)(3)/(5)-tan^(-1)(8)/(19)=(pi)/(4)tan^(-1)(1)/(5)+tan^(-1)(1)/(7)+tan^(-1)(1)/(3)+tan^(-1)(1)/(8)=(pi)/(4)cot^(-1)7+cot^(-1)8+cot^(-1)18=cot^(-1)(1)/(13)

PT tan^(-1)(3/4)+tan^(-1)(1/3)=tan^(-1)(13/9)

general solution of sec theta=(tan^(-1)(1)+tan^(-1)(2)+tan^(-1)(3))/(tan^(-1)1+tan^(-1)((1)/(2))+tan^(-1)((1)/(3))) is theta=

general solution of sec theta=(tan^(-1)(1)+tan^(-1)(2)+tan^(-1)(3))/(tan^(-1)1+tan^(-1)((1)/(2))+tan^(-1)((1)/(3))) is theta=